For this assignment, you will:
Enter your name: Daniel Jimenez Your name is: Daniel Jimenez The ASCII values are: 68 97 110 105 101 108 32 74 105 109 101 110 101 122Run the program again, this time redirecting output to a file called name.out. You can redirect output by running name like this:
This assignment is due at midnight on Wednesday, January 31, 2007.
Here is the program you are to type in. Substitute your name where it says Your Name.
#include <stdio.h> #include <unistd.h> /* * Name: Your Name * * Class: CS 2073 section 2 * * Purpose: * This program reads your name from standard input and prints * the decimal ASCII (American Standard Code for Information Interchange) * value for each letter. * * Input: * A single string terminated by a carriage return. * * Output: * "Your name is" followed by the input string, then * "The ASCII values are:" followed by a space-separated list of * decimal integers representing the ASCII codes for each character * in the input string. */ void print_ascii (char *); /* * main function * * This is the main program. It asks for your name, reads it into an array * of characters, and calls the `print_ascii' function to print the ASCII * values. */ int main (void) { char name[100]; /* prompt for the name */ printf ("Enter your name: "); /* read the name into the string `name' */ fgets (name, 100, stdin); /* print the name and ASCII values */ printf ("Your name is: %s", name); printf ("The ASCII values are: "); print_ascii (name); /* leave the program with exit code zero */ exit (0); } /* * print_ascii (char *) * * This function accepts a string and prints the ASCII value of each * character, then prints a newline */ void print_ascii (char *s) { int i, a; /* let i start at zero and continue until the i'th character * in s is null or carriage return, i.e., the end of the string */ for (i=0; s[i] && (s[i] != '\n'); i++) { /* convert s[i] to an integer and print it, * followed by a space */ a = (int) s[i]; /* notice that there's a space after %d here */ printf ("%d ", a); } /* print a newline */ printf ("\n"); }